|
Possible
Solutions for Homework 1 K
Foster, Economics of Environment, Eco B9526, CCNY Spring
2011 |
|
|
Write these as
and
so that they
are graphed as:

All these are in Excel sheet.
Find Qd = 25 – 3*7 = 4 and Qs = 2(7) = 14 so much more is supplied than demanded at this very high price. Only 4 is actually traded (the remainder piles up on shelves as unsold inventory) so PS and CS are as shown below:
![]()
![]()

CS is the small pink triangle; PS is the large blue trapezoid. The area of CS has height (8.33 – 7) = 1.33 and base of 4 so area is 2.67. The area of PS is the sum of (7 – 2)*4 + (2*4/2) = 20 + 4 = 24. DWL is the large triangle with base of 6 and height 5 so 15.
At P=2, 19 are demanded but just 4 are supplied so just 4 are traded. This is
![]()
![]()

Now CS is the large pink trapezoid and PS is the small blue triangle. So PS is 4 and CS is 2.67 + 20 = 22.67. DWL is still 15
The intersection is where 25 – 3P = 2P so P*=5 and Q*=10.

Now PS is the triangle with height 5 and base 10 so area 25; CS has height (8.33 – 5) and base 10 so area is (3.33*5)=16.67.


Substitute into the price
equation, that PD = PS + 1 so
and solve to
get
so
with Pd =5.4
and Ps = 4.4.
CS is the pink triangle with base 8.8 and height (8.33 – 5.4) so area is $12.9; PS is blue triangle with height 4.4 and base 8.8 so area is $19.6. Tax revenue is the yellow area: $1 per unit for 8.8 units so $8.8. DWL has base (10 – 8.8) = 1.2 and height 1 so area is 0.6.
Comparing these areas shows that we're always cutting up the same triangle (bounded by P-axis, supply and demand) into different segments:
|
Surplus
when P=7 |
Surplus
when P=2 |
Surplus
when P=5 |
Surplus
with tax |
|
|
CS |
2.67 |
22.67 |
16.67 |
12.9 |
|
PS |
24 |
4 |
25 |
19.36 |
|
Tax
revenue |
. |
. |
. |
8.8 |
|
DWL |
15 |
15 |
0 |
0.6 |
|
sum: |
41.67 |
41.67 |
41.67 |
41.66 |
Substitute to find
. This is a
part of a circle,

This is moving from the point
(0,10) to (1,
), a change of 0.05.
(Shown on Excel sheet.) Or use
calculus to find
. The Excel
sheet shows that at T=1 this is -0.1.
This is on the sheet or graphically

Since B and T enter symmetrically, we could just swap axes and the answer would be as above.
There is no way of saying. The "best" combination could be the
one which maximizes the function
but we have no
restrictions on the character of this U( ) function so there is no way of
giving an answer. If it were U=B or U=T
or U=B+T then there would be completely different answers. If both B and T have positive value then the
island should be on the PPF not the interior.
Question 3 likely gives a standard PPF, like that for B and T above, if we assume that it becomes steadily more difficult to get additional lumber output, as more land is cultivated for timber (and vice versa that cattle get more difficult, as more land is used for grazing).
Question 4 would have you draw 2 demand curves: the first has a vertical jump and the second is horizontal.
